Interpolation To Find Median. I thus tried to use b a b d c d. The interpolated median IM which is included in this report adjusts the median slightly upward or downward. Revision question for S1 for IAL and GCE. However they say the fractions a b and c d are equivalent.
The median is the middle observation in a sorted list of data. The interpolated median IM which is included in this report adjusts the median slightly upward or downward. Half of the values in the data set are less than or equal to the median and half are greater than or equal to it. I hope u get the idea. Anywhere between 305 and 405. One way to derive the formula is just to note that N2 is the number of data values BELOW the median so N2 - F is the number of data values in the median class that are below the median.
The median is the middle value which we can see is the 5th value so median 23 n1 The formula telling us which value we want is 2 where n is the number of data items.
This is a linear interpolation on the ogive graph as you suggested which finds where the actual median WOULD be if you assume that the data are uniformly distributed within the median class. So I use interpolation to find the said value. Revision question for S1 for IAL and GCE. Half of the values in the data set are less than or equal to the median and half are greater than or equal to it. Higher degree median-interpolation is also well-posed. The interpolated median IM which is used in these reports adjusts the median slightly upward or downward.